Unclear how to use #[interrupt] macro without deprecated --reexport-interrupt flag #830

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1. burrbull commented on Mar 26, 2024

   

   burrbull

   on Mar 26, 2024

   Last edited by burrbull

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   There have been planned some changes in cortex-m-rt 0.8 like moving interrupt in independent crate. But it is not done yet.
   Ask @adamgreig.
2. robamu commented on Jun 25, 2024

   

   robamu

   on Jun 25, 2024

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   I also stumbled into the issue, wondering why I could not use the interrupt macro, and I had to rebuild with the --reexport-interrupt flag.
3. royb3 commented on Aug 14, 2024

   

   royb3

   on Aug 14, 2024

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   You can use it without the flag. But you have to import your PAC's Interrupt enum as interrupt.

   use hal::pac::Interrupt as interrupt;
   use cortex_m_rt::interrupt;

   That's basically what the --reexport-interrupt flag does as well. Not sure if there's any value in doing this over using the deprecated flag for now.

   ❤️React with ❤️5Reacted by ibl-bkoenig, Seki Inoue, vasilNnikolov, Nathan Krause and Bnyro
4. Bnyro commented on Apr 13, 2026

   

   Bnyro

   on Apr 13, 2026

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   To save any future reader time with debugging:

   If you are trying to use this with rtic and come across some linker errors regarding the interrupt vector table, e.g. link.x:49: symbol not found: DefaultHandler_:

   Make sure to include the import to use cortex_m_rt::interrupt;. I thought rtic would do that by itself, but apparently it doesn't.

   E.g., this would look like

   Details

   use your_pac as _;
   use cortex_m_rt::interrupt;
   #[rtic::app(
   
   device = your_pac,
   
   dispatchers = [UARTE0],
   
   )]
   
   mod app {}
   
   

   For reference, that's what --reexport-interrupt does:

   #[cfg(feature = "rt")]
   pub use self::Interrupt as interrupt;
   #[cfg(feature = "rt")]
   pub use cortex_m_rt::interrupt;

   Sorry if this looks obvious to most of you, but understanding this earlier would have probably saved me hours :)